Rachel has 20 coins composed of nickles, dimes and quarters
amounting to $3.70. Her quarters are twice the number of her dimes, the number
of nickels can be computed as follows:
If X= the number of
dimes at .10 each
Then 2x= the number
of quarters at .25 each and
20-(X-2X)= the number of nickels at .05 each
<span>
<span><span>
<span>
The equation will be:
X(.1)+2(X).25+(20-X-2X).10=3.70
</span>
</span>
<span>
</span>
<span>
<span>
.1X+2X(.25)+(20-X-2X).05=3.70
</span>
</span>
<span>
<span>
.1X+.5X+(20-3X).05=3.70
</span>
</span>
<span>
<span>
.6X+(1-.15X)=3.70
</span>
</span>
<span>
<span>
.6X+1-.15X=3.70
</span>
</span>
<span>
<span>
.45X=3.70-1
</span>
</span>
<span>
<span>
.45X=2.70
</span>
</span>
<span>
<span>
X=2.70/.45
</span>
</span>
<span>
<span>
X=6 number of dimes
</span>
</span>
<span>
<span>
2X=12 number of quarters
</span>
</span>
<span>
<span>
20-6-12=2 number of nickels
</span>
</span>
</span></span>