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Alex
3 years ago
9

About how many feet of fencing are needed to go around the pool path? Use 3.14 for Pi. 88 ft 100 ft 176 ft 201 ft

Mathematics
1 answer:
denis23 [38]3 years ago
7 0

Complete question :

A circular swimming pool has a radius of 28 ft. There is a path all around the pool that is 4 ft wide. A fence is going to be built around the outside edge of the pool path.

About how many feet of fencing are needed to go around the pool path

Answer:

201 feets

Step-by-step explanation:

The Circumference of a circle, C :

C = 2 * pi * r

r = Radius ; pi = 3.14

The entire Radius = pool radius + pathnaroind the pool = 28 + 4 = 32

Hence, the Circumference, which gives the value of fencing required is :

C = 2 * 3.14 * 32

C = 200.96 ft

C = 201 feets

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a map of a rectangle park has the length of 4inches and a with of 6 inches. It uses a scale of 1 inch every 30 miles. What is th
ratelena [41]

Answer:

720 mi²

Step-by-step explanation:

The map has a scale of 1 in: 30 mi, meaning that for every inch you see on the map, in the real-life location, it will measure 30 miles. So we can find the area of the park on the map and then turn it into miles using the scale:

Area of a rectangle:

A=bh

Replace the known values:

A=(4)(6)\\ A=24

The area on the map is 24 mi², we can turn it to miles using the scale by multiplying our result with 30:

A=(24)(30)\\ A=720

And last but not least, don't forget to put the unit!

4 0
3 years ago
Find parametric equations for the line through the point (0, 3, 2) that is parallel to the plane x + y + z = 5 and perpendicular
kozerog [31]
Hello : 
let A(0,3,2) and (Δ) this line , v vector   parallel to (<span>Δ).
M</span>∈ (Δ) : vector (AM) = t v..... t ∈ R

1 )    (Δ)  parallel to the plane x + y + z = 5 : let  : n an vector <span>perpendicular 
to the plane : n </span>⊥ v   ....   n(1,1,1) so : n.v =0  means : n.vector (AM) = 0
(1)(x)+(1)(y-3)+(1)(z -2) =0      ( vector (AM) = ( x, y -3 , z-2 )
x+y+z - 5=0 ...(1)

2)  (Δ) perpendicular to the line (Δ') : x = 1+t  , y = 3 - t , z = 2t :
vector (u) ⊥ v     .... vector(u) parallel to (Δ')  and vector(u) = (1 , -1 ,1)
vector (u) ⊥ vector (AM) means : 
(1)(x)+(-1)(y-3)+(2)(z -2) =0
x - y+2z - 1 = 0 ...(2)
so the system : 
x+y+z - 5=0 ...(1)
x - y+2z - 1 = 0 ...(2)
 (1)+(2) :   2x+3z - 6 =0
x = 3 - (3/2)z
subsct in (1) :    3 - (3/2)z  +y +z - 5 =0
y = 1/2z +2
let : z=t     
an parametric equations for the line (Δ) is :  x = 3 - (3/2)t
                                                                      y = (1/2)t +2
                                                                      z=t

verifiy : 
1) (Δ)  parallel to the plane x + y + z = 5 : 
(-3/2 , 1/2 ,1) <span>perpendicular to (1,1,1)
</span>because : (1)(-3/2)+(1)(1/2)+(1)(1) = -1 +1 = 0
2) (Δ) perpendicular to the line (Δ') :
 (-3/2 , 1/2 ,1) perpendicular to (1,-1,2)
because : (1)(-3/2)+(-1)(1/2)+(1)(2) = -2 +2 = 0
A(0, 3, 2)∈(Δ) : 
0 = 3-(3/2)t
3 = (1/2)t+2
2 =t
same :  t = 2

3 0
3 years ago
11 / 16 = p + 4 / 12
butalik [34]

Answer:

p = 17/48 or 0.354

Step-by-step explanation:

11/16 = p + 4/12

subtract 4/12 from both sides

11/16 - 4/12 = p

convert so you have a common denominator

3(11/16) - 4(4/12)

33/48 - 16/48

= 17/48

p = 0.354

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IRINA_888 [86]

Answer: 639

Step-by-step explanation:

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Darya [45]
You would divide 456 miles by the number of gallons used to get the answer of 38 miles per gallon.
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