The mean is 9.6
3+8+10+12+15= 48/5= 9.6
X would equal 2.7 //////////////
Answer:
7m
Step-by-step explanation:
18/6 = 3
24/8 = 3
21/x = 3
21/3 = 7
x = 7
We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation
.
To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate
and solve for t as:



Now we will switch sides:

Let us take natural log on both sides of equation.

Using natural log property
, we will get:










Therefore, it will take
years for area of the glacier to decrease to 15 square kilo-meters.