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Norma-Jean [14]
3 years ago
12

How many common fractions strictly between 0 and 1 have a denominator of at most 6 when written in lowest term

Mathematics
2 answers:
spayn [35]3 years ago
7 0

1/6

5/6

4/5

3/5

2/5

1/5

3/4

1/4

2/3

1/3

1/2

zimovet [89]3 years ago
4 0

I believe eleven in total

1/6  5/6  4/5  3/5  2/5  1/5  3/4  1/4  2/3  1/3  1/2

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Can anyone assist me with this problem ?
Orlov [11]

Answer,

C

Step-by-step explanation:

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3 0
2 years ago
Sunscreen should be applied every 2 hours. Over the summer, Cece spends at least 84 hours outside.
maria [59]

Answer:

42

Step-by-step explanation:

84 divide 2

answer 42

answer =42

4 0
2 years ago
Solve for h.<br>3/7 = h/14 - 2/7​
AleksAgata [21]

Answer:

10

Step-by-step explanation:

Multiplying both sides by 14

2*3=h-(2*2)

6=h-4

h=6+4

h=10

3 0
3 years ago
Read 2 more answers
HELP ME ! beautiful people that are good at math
ANTONII [103]
-3(-4y+3) +7y
Expand
12y-9+7y
Add like terms
19y-9
8 0
2 years ago
a random sample of 510 high school students has a normal distribution. The sample mean average ACT exam score was 21 with a 3.2
34kurt

Answer:

CI = 21 ± 0.365

Step-by-step explanation:

The confidence interval is:

CI = x ± SE * CV

where x is the sample mean, SE is the standard error, and CV is the critical value (either t score or z score).

Here, x = 21.

The standard error for a sample mean is:

SE = σ / √n

SE = 3.2 / √510

SE = 0.142

The critical value is looked up in a table or found with a calculator.  But first, we must find the alpha level and the critical probability.

α = 1 - 0.99 = 0.01

p* = 1 - (α/2) = 1 - (0.01/2) = 0.995

Using a calculator or a z-score table:

P(x<z) = 0.995

z = 2.576

Therefore:

CI = 21 ± 0.142 × 2.576

CI = 21 ± 0.365

Round as needed.

8 0
3 years ago
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