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liq [111]
3 years ago
14

A silver coin rubs vigorously against a wool cloth. The cloth becomes positively charged. Which statements are true?

Physics
2 answers:
Darina [25.2K]3 years ago
6 0
The wool cloth gained protons.
TiliK225 [7]3 years ago
4 0

the good answer is that the silver coin gains electrons and the wool clothes loses electrons

hope i help

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Two 75 W (120 V) lightbulbs are wired in series, then the combination is connected to a 120 V supply. Part A How much power is d
Elenna [48]

Answer:

<em>300 W</em>

<em></em>

Explanation:

power of each bulb P = 75 W

voltage in the circuit = 120 V

we know that electrical power P = IV    ....1

and V = IR

we can also say that I = V/R

substituting for I in  equation 1, we have

P = V^{2}/R    ....2

The total total power in the circuit = 75 x 2 = 150 W

from equation 2, we have

150 = 120^{2} /R

R = 120^{2}/150 = 96 Ω    this is the resistance of the whole circuit.

This resistance is due to the two light bulbs, for each light bulb since they are arranged in series

R = 96/2 = 48 Ω

From P =  V^{2}/R  

for each light bulb, power is

P = 120^{2} /48 = <em>300 W</em>

8 0
3 years ago
What is the equivalent resistance of the circuit?
Ivanshal [37]

Answer:

Since the wire is not splitting at any point in the circuit,

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8 0
3 years ago
How does the viscosity of a liquid affect the definition of a liquid?
yaroslaw [1]

Viscosity is another type of bulk property defined as a liquid's resistance to flow. When the intermolecular forces of attraction are strong within a liquid, there is a larger viscosity. An example of this phenomenon is imagining a race between two liquids down a windshield.

4 0
3 years ago
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A solar oven can be created by focusing the sun's rays to a point using a _________ mirror.
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7 0
3 years ago
A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is
ella [17]

Answer:

1.97 seconds

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t = Time taken

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v = Final velocity

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s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0

Solving the above equation we get

t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89

So, the time the package was in the air is 1.97 seconds

3 0
3 years ago
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