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leva [86]
4 years ago
7

Rewrite y = 9x + 7 into standard form. Pleas help!

Mathematics
2 answers:
Sonbull [250]4 years ago
8 0

-9x + y = 7 is your answer have a good day

Sophie [7]4 years ago
3 0

9x - y = -7 is the answer

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Answer: (-∞, 65/3)

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Please help!! Find the domain and range of the following function ƒ(x) = 5|x - 2| + 4
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Step-by-step explanation:

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Jill has a poster hanging in her room whose width is 212 in. shorter than its length. The perimeter of the poster is 103 in. How
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The poster is a rectangle. 
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where L is the length and W is the width of a rectangle.
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4 0
3 years ago
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

b

 h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

c

 h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

Step-by-step explanation:

From the question we are told that

    h(x) =  x^2  + x  + 5

and  

    g(x) = \sqrt[4]{x} + 3

Considering first question

Now we are told  g(h(x))

i.e

        g(h(x)) =  [x^2 + x + 5 ]^{\frac{1}{4} } + 3

=>     g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

Considering second  question

   Now we are told  h(g(x))

i.e

    h(g(x)) =  [x^{\frac{1}{4} } + 3]^2 +  x^{\frac{1}{4} } + 3 + 5

=> h(g(x)) =  x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}}  + 8

=>  h(g(x))  = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17

=>  h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

Considering third question

         h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] +  5

=>       h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

8 0
4 years ago
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