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vodomira [7]
3 years ago
6

Don't write it seems to smart

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0
I think you miss types your question
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If the height of Mount Everest is about 8.8×103 meters, and the height of the Empire State Building is about 3.8×102 meters, whi
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Mount Everest is about 23<span> times as tall as the Empire State Building. Hope that helps!</span>
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4 years ago
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You got two questions wrong on your ten question quiz. What percent did you earn in the grade-book?
hjlf

Answer:

80% that is what you got is this a test question  or no?

Step-by-step explanation:


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3 years ago
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Please awnser questions, no links, no I dont know
Mrac [35]

Answer:

330cm

Step-by-step explanation:

The formula to find the surface area of a rectangular prism is 2(lh+hw+lw)

(lh) in this formula is length times height

(hw) is height times width

(lw) is length times width

To find the answer to this problem lets make the height 3/5cm the width 10cm and the length 15cm

so now you would do (15*3/5) which is 9. This solve (lh)

then you would find (3/5*10) which is 6. This solves (hw)

and lastly you would find (15*10) which is 150. This solves (lw)

Now that you now the value of each one of these you replace it in the equation as so: 2(9+6+150)

now you solve the brackets which leaves us with 2(165)

now you multiply 2 with 165

and the answer is 330cm

Surface area = 330cm

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3 years ago
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Write an algebraic expression for each verbal expression. Then simplify, indicating the properties used. 4 times the difference
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4(f ^2-g)+f^2+2g is your answer
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3 years ago
The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
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Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

3 0
3 years ago
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