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Nadusha1986 [10]
3 years ago
14

For a project called "The Sheep Market", Aaron Koblin collected drawings of sheep from strangers on the Internet. He posted the

task on the Amazon Mechanical Turk crowdsourcing platform for 2 cents, and over the course of 40 days, at a rate of about 11 sheep per hour, he collected 10,000 drawings from 7,599 IP addresses. Which of these is true about his decision to crowdsource the sheep drawings?
Computers and Technology
1 answer:
Furkat [3]3 years ago
6 0

Answer:

Aaron could expect a diversity in the style of the sheep drawings.

Explanation:

Crowdsourcing is a simply a sourcing model in which an individual or organizations get goods and services, ideas and finances, from a large, relatively open and often rapidly growing group of internet users.

It makes it easier for participants to achieve a cumulative result through working differently on the same project. That is to say, it provides work between participants to achieve a cumulative result.

Its benefits is that, Crowdsourcing allows businesses to perform tasks more quickly than when a single employee is working alone. Again, Breaking up a project into a collection of smaller pieces and providing these pieces to a larger group of workers hastens the completion of projects. Overall, crowdsourcing presents a more efficient way to do work.

From the Question, Aaron was able to get different pictures of sheep in their numbers also because he used crowsourcing on amazon.

He got a variety of pictures and so many in such a short time for his project "The Sheep Market".

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Nathan took a picture of his friends while they were on a field trip. He wants upload this picture to a photo-sharing site. He w
Alenkinab [10]

Answer:

photoshop

Explanation:

(if there are answer choices pls comment them and  I'll pick an answer from them, but this is just my best guess. : )

5 0
2 years ago
Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a
yaroslaw [1]

Answer:

<em>The program doesn't use comments; See explanation section for detailed line by line explanation</em>

<em>Program starts here</em>

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

<em>Line by Line explanation</em>

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

<em>This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed</em>

<em>      if score >= 90 and score <= 100:</em>

<em>            print("Letter Grade: A")</em>

<em />

<em>This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed</em>

<em>      elif score >= 80 and score <= 89:</em>

<em>            print("Letter Grade: B")</em>

<em />

<em>This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed</em>

<em>      elif score >= 70 and score <= 79:</em>

<em>            print("Letter Grade: C")</em>

<em />

<em>This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed</em>

<em>      elif score >= 60 and score <= 69:</em>

<em>            print("Letter Grade: D")</em>

<em />

<em>This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed</em>

<em>      elif score >= 0 and score <= 59:</em>

<em>            print("Letter Grade: F")</em>

<em />

<em>If input score is less than 0 or greater than 100, "Invalid Score" is printed</em>

<em>      else:</em>

<em>            print("Invalid Score")</em>

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0
2 years ago
You are researching RAM for a computer you are building for a friend who will be using the system as a home office server for he
pashok25 [27]

Answer:

ECC RAM

Explanation:

ECC RAM is the most popular Random Access Memory out there that is used by most business servers. Dealing with big data for most huge businesses is crucial. The need to prevent loss of data requires that they purchase ECC RAM. ECC RAM automatically protects the systems from potential errors that occur in memory. Any abrupt changes in temporary data stored in ECC RAM are automatically corrected. This is achieved by an additional memory chip that acts as error detection for the other eight RAM chips.

8 0
3 years ago
Dione has created a PowerPoint presentation that has several common nouns, names of products, etc. He is
svetlana [45]

Answer:

D. Add

Explanation:

PowerPoint application can be defined as a software application or program designed and developed by Microsoft, to avail users the ability to create various slides containing textual and multimedia informations that can be used during a presentation. Some of the features available on Microsoft PowerPoint are narrations, transition effects, custom slideshows, animation effects, formatting options etc.

In this scenario, Dione has created a PowerPoint presentation that has several common nouns, names of products, etc. He is running Spell Checker and does not want to be notified in regard to these words in this presentation or in any other presentation created on this computer. Hence, the option he should choose is Add. This would be used to automatically add a list of all the common nouns.

3 0
2 years ago
Read 2 more answers
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
2 years ago
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