Answer:
d
Explanation:
cause people need a care for there incedents that not expected thats why people need help prevent from a risk to save people lives
Answer:
D. O(NlogN)
Explanation:
The computation of the overall algorithm cost is as follows:
Given that
O(logN) + O(N) × O(logN) + 1
In the case of complexity we considered the high order that dominates the other terms
Thus, that term would be
O(N) × O(logN)
It could be rewrite as
O(NlogN)
Hence, the correct option is D.
All the other options are wrong
Answer:
implements CSMA/CD over legacy shared half-duplex media; enables IPv4 and IPv6 to utilize the same physical medium; integrates Layer 2 flows between 10 Gigabit Ethernet over fiber and 1 Gigabit Ethernet over copper
Explanation:
I hope it helped . follow me on ig minisized._miyaa
Hi, the photo doesn’t show the question on what to answer, all I see are empt boxes, if you message me the question I will answer it for you!
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
