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Ksivusya [100]
3 years ago
10

Is 7/6 less than 1/2?

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
8 0

Answer:

No

Step-by-step explanation:

7/6 is equal to 1 1/6

Assoli18 [71]3 years ago
4 0

Answer:

no

Step-by-step explanation:

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the store however, lost the original $100 bill plus the $70 in merchandise, so they have -$170.
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What is the slope of this graph?
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-3/4

Step-by-step explanation:

First, pick two coordinates.

(0,2) and (4,-1)

Then do the rise over run or y/x.

The y is 3 and the x is 4. That is 3/4.

Since the line is going down, it will be negative.

The answer is -3/4.

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3 years ago
Rita is hosting movie night tonight. To get ready, she makes popcorn. She fills both a small bowl and a large bowl to the top wi
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Answer: The smaller bowl



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8 0
3 years ago
What is the median of this set of data?
Vladimir [108]

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8 0
3 years ago
Read 2 more answers
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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