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viva [34]
3 years ago
9

Samuel measured three ropes as 3and 63/80 feet, 3and 1/5 feet, and 3and 11/20feet. Put the measurements of the ropes in order fr

om lease to greatest.
Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
3 1/5, 3 11/20, 3 63/80
Sauron [17]3 years ago
7 0
The measurements in the order given are:
3 63/80, 3 1/5, 3 11/20
We can make the common denominator 80 so:
3 63/80 stays the same, 3 1/5 both sides of the fraction are multiplied by 16 so it becomes 3 16/80, 3 11/20 both sides of the fraction are multiplied by 4 so it becomes 3 44/80
In ascending order the new fractions are:
3 16/80, 3 44/80, 3 63/80.
So in order from least to greatest, the fractions are:
3 1/5, 3 11/20, 3 63/80

Hope this helps :)
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Simplify 8(xy + 8) + 1. 8xy + 9 8xy + 65 8xy + 73
mixer [17]

64x2y2 the twos are powers of ten so you put them up top.

8 0
4 years ago
Read 2 more answers
Henry has two pixie sticks full of delicious sugar. Henry loves to share. It just so happens that there are two other friends ne
Effectus [21]

Answer: 14.7 grams

Step-by-step explanation:

Given : Henry has two pixie sticks full of delicious sugar.

Each pixie stick has 22 grams of sugary goodness.

Then, Total sugary goodness in 2 pixie sticks= 2\times22=44\text{ grams}

Total persons = 3   [Including himself]

If he divides 2 sticks evenly among 3 persons , then the amount of sugary goodness each persons will receive

= Total sugary goodness in 2 pixie sticks divided by 3

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Hence, He will share 14.7 grams of sugary goodness with each of his friends.

4 0
3 years ago
Help please asap!!!!!!!!!
Alchen [17]
The answer should be B.
7 0
3 years ago
I NEED HELP
jeka94
B has more because 10/5 is 2 and 8/12 is less
4 0
3 years ago
Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too?
rusak2 [61]

<em>Question 5</em>

Vertical angles are <u>congruent</u>. Therefore, 3y=\boxed{150}. The sum of two supplementary angles equals \boxed{180^{\circ}}.

Therefore, 6x+150=\boxed{180}

<em>Question 6</em>

\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}

<em>Question 7</em>

<em />\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}

<em>Question 8</em>

<em />7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}

6 0
2 years ago
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