The answer is <span>20.3896551724</span>
9514 1404 393
Answer:
C. 12cm
Step-by-step explanation:
The equation for the perimeter of the rectangle is ...
P = 2(L+W)
34 = 2(n +m)
Solving for m, we get
m = 17 -n . . . . . . . divide by 2, subtract n
__
The Pythagorean theorem gives the relationship between the sides and the hypotenuse
m^2 +n^2 = (n+1)^2
(17 -n)^2 +n^2 = (n +1)^2 . . . . . . substitute for m
289 -34n +n^2 +n^2 = n^2 +2n +1 . . . . eliminate parentheses
n^2 -36n +288 = 0 . . . . . . . put in standard form
(n -12)(n -24) = 0 . . . . . . . . . factor
n = 12 . . . . . . . . . . n=24 is an extraneous solution here
The value of n is 12 cm.
<span>
If BA is d units the CB must be 2d units. B is on the x-axis, 2d units
right of C so its coordinates are (2d, 0). A is d units above B at (2d,
d). </span>
Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
4
Step-by-step explanation:
The mode is the number that appears the most!!!!
Now lets solve :)
2, 2, 3, 3, 4, 4, 4, 4,
There are 2 2s.
There are 2 3s.
There are 4 4s.
The mode is 4!!! :)
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