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devlian [24]
3 years ago
5

The domain of the function given below is the set of all real numbers greater than 1 F(x) =(1/2)^x A. True B false

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

The given statement is False.

Step-by-step explanation:

We have been given the function f(x)=(\frac{1}{2})^x and the domain of this function is all real numbers greater than 1.

We know that the domain is the set of x values for which the function is defined.

We can see that for any real values of x, the function is defined. Therefore, the domain of the given function is the set of all real numbers.

Therefore, the given statement is False.

Law Incorporation [45]3 years ago
7 0

it is false for APEX


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.08 x .04 is the right answer

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A health club charges a $130 yearly membership fee and $3 for each day a member uses the health facilities. If the member paid $
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This is the answer for your question: y=3x+130
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A system of equations is shown below:
JulijaS [17]
X+y=3

Subtract x from both sides

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Substitute

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6 0
3 years ago
How do I simplify (6^-2)(3^-3)(3 x 6)^4? Not the answer, just the simplified expression.
Mazyrski [523]

The simplification form of the provided expression is 108 after applying the integer exponent properties.

<h3>What is integer exponent?</h3>

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

We have an expression:

=\left(6^{-2}\right)\left(3^{-3}\right)\left(3\:\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\left(3\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\cdot \:81\cdot \:1296

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Thus, the simplification form of the provided expression is 108 after applying the integer exponent properties.

Learn more about the integer exponent here:

brainly.com/question/4533599

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5 0
1 year ago
Please answer with process
laila [671]

\mathsf{Given : a - b = 5}

\mathsf{Squaring\;on\;both\;sides,\;we\;get :}

\mathsf{\implies (a - b)^2 = 5^2}

\mathsf{\implies a^2 + b^2 - 2(a.b) = 25}

\mathsf{Given : a^2 + b^2 = 29}

\mathsf{\implies 29 - 2(a.b) = 25}

\mathsf{\implies 2(a.b) = 29 - 25}

\mathsf{\implies 2(a.b) = 4}

\mathsf{\implies (a.b) = 2}

6 0
3 years ago
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