Step-by-step explanation: Given that a school wants to put on a dance recital. The programs of Middle school dancer will be short of 4 minutes each and programmes of High school performers will be long of 7 minutes each.

Number of middle school dances is "M" and number od high school dances is "H".

Since there cannot be more than 10 dances all together, so fisrt inequality can be written as

$\textup{M}+\textup{H}\leq 10.$

Also, the entire recital must take maximum 90 minutes, so the second inequality can be written as

$4\textup{M}+7\textup{H}\leq 90.$

Thus, the pair of inequalities is

$\textup{M}+\textup{H}\leq 10,\\\\4\textup{M}+7\textup{H}\leq 90.$

6 0

3 years ago

12=10(s+4)+50 what is the written problem to this can you help me with the answer

muminat

Answer:

s = -7.8

Step-by-step explanation:

from the question 12=10(s+4)+50

<u>first step</u>

open the bracket and evaluate for the value of s

12=10(s+4)+50

12 = 10s + 40 + 50

12 = 10s + 90

collect or combine the like terms

12-90 = 10s

-78 = 10s

divide both side by 10

-78/10 = 10s/10

-7.8 = s

therefor s = -7.8

8 0

3 years ago