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2 years ago

The population of Virginia is 30% less than the population of Georgia. If

Mathematics

1 answer:

Advocard [28]2 years ago

3 0

7,150,000

The population of Georgia is 10,500,000.

The population of Virginia is 30% less than that.

So the population of Virginia is 10,500,000 - 30% which equals 7,150,000

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Eliminate the parameter in the equations x = 5cos(t) – 7 and y = 5sin(t) 9. how can the rectangular equation be described?

Maksim231197 [3]

Recall that for all t,

cos²(t) + sin²(t) = 1

Now,

x = 5 cos(t) - 7 ⇒ (x + 7)/5 = cos(t)

y = 5 sin(t) + 9 ⇒ (y - 9)/5 = sin(t)

so that substituting into the identity above, we get

((x + 7)/5)² + ((y - 9)/5)² = 1

which we can rewrite as

(x + 7)²/25 + (y - 9)²/25 = 1

(x + 7)² + (y - 9)² = 25

and this is the equation of a circle centered at (-7, 9) with radius 5.

3 0

1 year ago

Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio

Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

$SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2} } }{N} }$

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

$X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\$

3. Caclulate Standard deviation:

$SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2} } }{5} }$

$SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251$

7 0

2 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago

Which of the following inequalities is correct?

Mariana [72]

Is the answer -5 > 0?

7 0

2 years ago

G(-4) = <br> anyone know the answer to this

Scorpion4ik [409]

G(-4) =1
i hope this helps!

4 0

2 years ago