Answer:
8022.
Step-by-step explanation:
Let x be the number of years after 2010.
We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.
We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.
Since we know that an exponential function is in form:
, where,
a = Initial value,
b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.
Let us convert our given decay rate in decimal form.

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:


Let us find x by subtracting 2010 from 2019.

Upon substituting x=9 in our function we will get,



Therefore, the population of fish in 2019 will be 8022.
Same as any other midpoint of line segment or two points, it is the average of the two points x and y coordinates...
mp=((x1+x2)/2, (y1+y2)/2)
mp=((-6+16)/2, (-9+5)/2)
mp=(10/2, -4/2)
mp=(5, -2)
Arc length = 2 π R (C/360)
where:
C is the central angle of the arc
R is the radius of the arc
arc length = 2 π R (137/360) = 2.39R
False congruent figures mean the run equal
Answer:
2329 are girls out of 37 boys in school in 2366 total