Question

A bag contains 3 red marbles 4 blue marbles and 7 Green marbles if two marbles are drawn out of the bag what is the probability to the nearest 1000th that both marbles drawn will be red

Answer 1

Answer:

0.368

Step-by-step explanation:

Number of red marbles= 3

Number of blue marbles= 4

Number of green marbles= 7

Total number of marbles= 3+4+7= 14

Let the first ball is taken out to be red

P(R)=$\frac{3}{14}$

than again a second ball is drawn, number of balls left= 14-1=13

Number of red= 2

P(R)=$\frac{2}{13}$

Total probability=$\frac{3}{14}$+$\frac{2}{13}$

Total probability= 0.368

Hence, the correct answer is 0.368