Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
What 2 numbers multiply to get 16 and add to get 10?
2 and 8
(t+8)(t+2)
Plug in the values of x and y into each ineqaulity and see which one fits
You'll find it is d
Dang this is too much to read i nearly understand the question
Answer:
8+16+2= 24 legs on ground
Step-by-step explanation:
