Question

Question 16 of 40

Answer 1

Answer:

Option C. $(x+3)^2=13$

Step-by-step explanation:

we have

$x^2+6x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^2+6x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^2+6x+3^2=4+3^2$

$x^2+6x+9=13$

Rewrite as perfect squares

$(x+3)^2=13$