Write an equation in slope intercept form. Y-2/3x=3;(-6,1)
1 answer:
We won't be using the given point (-6,1), since it won't really help us to get our answer.
Add 2/3x to both sides of the equation.
The 2/3x on the left side will cancel each other out.
This equation is in the form y=mx+b, which is slope intercept form.
Let me know if you need any clarifications, thanks!
You might be interested in
Answer:
10. 20.9°
11. 73.2°
Step-by-step explanation:
The inverse sine function is used to find the angle from its sine value.
<h3>10.</h3>In each case, the equation is of the form ...
a/sin(x) = b/c
Multiplying both sides by c/b·sin(x), we find the solution is ...
sin(x) = ac/b . . . . . find sin(x)
x = arcsin(ac/b) . . . . . find the corresponding angle
For the given values a=7.2, b=13, c=sin(40°), we have ...
x = arcsin(7.2sin(40°)/13) ≈ 20.9°
<h3>11.</h3>For the given values a=6.53, b=√40, c=sin(68°), we have ...
x = arcsin(6.53sin(68°)/√40) ≈ 73.2°
Answer:
- f(x) = 3(x - 3)^2 - 3
Step-by-step explanation:
<u>Let the base function be</u>
- f(x) = ax^2
<u>It has the vertex at (3, -3), so it is translated 3 units right and 3 units down:</u>
- f(x) = a(x - 3)^2 - 3
It has zero's at (2, 0) and (4, 0)
<u>Substitute and solve for a:</u>
- a(x - 3)^2 - 3 = 0
- a(2 - 3)^2 = 3
- a = 3
or
- a(4 - 3)^2 - 3 = 0
- a = 3
<u>So the function is:</u>
- f(x) = 3(x - 3)^2 - 3
<em>See the attached</em>
