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2 years ago

Number 16 what is the answer

Mathematics

2 answers:

dimaraw [331]2 years ago

4 0

Cos 45=7 under root 2 /AB
1 / Under root 2 = 7 under root 2 / AB
AB=14
Ans = 14(b)

VMariaS [17]2 years ago

4 0

I am pretty sure your answer is B.

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If the triangles are congruent, then X=?

steposvetlana [31]

Answer:

Hi there!

The correct answer to this question is: x=3

Step-by-step explanation:

because these two triangles are similar, that means the hypotenuse are similar. which means you can set the sides equal to each other like this:

13 = 4x + 1 minus one on both sides and you should get 4x = 12 and then divide 4 on both sides and you should finally get x = 3

7 0

2 years ago

Brainly do ur magic pls.?

jok3333 [9.3K]

1. 3y

multiplying 3 and y together gets 3y

2. y-5

5 less implies that we subtract 5 from y

3. y+7

adding 7 to y, self-explanatory

4. 9y

same thing as #1

5. $\frac{y}{8}$

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8 0

3 years ago

Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)

SashulF [63]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 {x}^{2} + 4x + 6)(7x + 5)$

$= \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)$

$= \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30$

Combining like terms, we have

$= \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30$

$= \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

3 0

2 years ago

Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\df

Amanda [17]

Answer:

$\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

$P=\dfrac{W}{t}$

Unit of Work = $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}$

Unit for Time = s

Therefore, the Unit of Power

$=$Unit for W \times \dfrac{1}{\text{Unit for time}}$

$=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2} \times \dfrac{1}{s} \\=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

An appropriate unit for power is: $\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}$

3 0

2 years ago

Question 1

astra-53 [7]

Answer: 1

Step-by-step explanation:

4 0

2 years ago