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madam [21]
3 years ago
6

Patricia was on a raft in the ocean. She hoped to get closer to a nearby island, but the wind was tricky. During one hour, she p

addled a lot and got 10 feet closer. During the next hour, she gave up and the wind pushed the raft 95 feet farther away. Model the distance Patricia travels toward the island and as a sun
Mathematics
1 answer:
nordsb [41]3 years ago
5 0

Answer:

85 feet

Step-by-step explanation:

95feet-10feet=85feet

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line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to
Andrews [41]
Since the line is parallel to AB, the two slopes are the same
        
                      slope of AB = m = (y₂-y₁)/(x₂-x₁)
                                     
                                           m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
                      The origin    P(0,0) 
                                       y=mx
                                       y= -\frac{5}{3}x   Solution
8 0
3 years ago
Read 2 more answers
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
How much more is 4/6 Than 5/6
Sveta_85 [38]
5/6 is 1/6 more than 4/6. All you had to do is subtract 4/6 from 5/6 to get <u><em>1/6</em></u>.
6 0
3 years ago
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Evaluate 7(-4) - |-6| + |4|
Zanzabum

\red { \green {\boxed {\boxed{Answer}}}}

= 7( - 4) -  | - 6|  +  |4|

=  - 28 -  | - 6 |  +  |4|

=  - 28 - 6 +  |4|

=  - 34 +  |4|

=  - 34 + 4

=  - 30

The absolute value of a real number a is a when a≥0, or -a when a<0. The absolute value of -6 is 6. The absolute value of 4 is 4.

 ‍ 

#IfWrongPleaseReport

#StudyTogetherWithMe

#ILoveMath

7 0
3 years ago
Help me please its super easy
yanalaym [24]

Your answer would be the first option 10^5.

Hope this helped.

6 0
3 years ago
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