Answer:
0.095
Explanation:
Phenylkentonuria is a disease caused by a recessive allele.
The frequency of the recessive allele + the frequency of the dominant allele equals 1.
The frequency of the recessive allele is q = 0.05
The frequency of the dominant allele then is p = 1 - q = 0.95
If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .
2pq=2× 0.05 × 0.95
2pq=0.095
The heterozygote frequency in the population is 0.095
The correct answer for this question would be C) At seafloor spreading centers or the third option.
Answer:
Taking shorter showers or turning off the faucet while brushing your teeth can reduce water waste in your home. Only use your dishwasher or washing machine when there is a full load, and switch to energy-saving appliances if possible.
Explanation:
Last night Jasmine and Jay amount combined is $150+$130=$280
amount donated to charity is 1/4 of $280= $70
amount spent at an amusement park is` 40/100 x $210= $84
the remaining money = 280- (70+84)= $126
35% of their original amount is 35/100x$280=$98
so Jay's claim is not correct because the remaining money is $126 and not $98 as she Jay claims.
q=0,78
To calculate the frequency of the allele we use the Hardy-Weinberg equation. The Hardy-Weinberg equation is used to calculate the genetic variation of a population at equilibrium. If the alleles are A and a, p is the frequency of the allele A and q is the frequency of the allele a. Hardy-Weinberg equation for alleles A and a:
p² + 2pq + q² = 1
p² is the frequency of the homozygous genotype AA, 2pq is the frequency of the heterozygous genotype Aa and q² is the frequency of the homozygous genotype aa.
p²+2pq+q²=(p+q)²=1
p+q=1
<span>If p=0,22 q=1-0,22=0,78</span>
