Answer:
1) Alternating Interior angels supplementary
2) Corresponding angels congruent
3) Alternating Interior Angles congruent 93º
4) Alternating Interior Angles congruent 96º if it says 96º on the paper it's blurry
Step-by-step explanation:
Answer:
100 times
Step-by-step explanation:
doesn't matter if the number is in the same place value so, the answer is 100 times.
Answer:
-6.1 - (-3.13) = -2.97
Step-by-step explanation:
two negative symbols = a positive.
Answer:
a) 2.66
b) 9
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
part A: what is the standard deviation of the sampling distribution of x hat? show your work.
We have that
. So
![s = \frac{\sigma}{\sqrt{n}} = \frac{8.4}{\sqrt{10}} = 2.66](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%20%5Cfrac%7B8.4%7D%7B%5Csqrt%7B10%7D%7D%20%3D%202.66)
PartB: what does the sample size need to be if you want the standard deviation of the sampling distribution of x hat to be 2.8?
This is n when
. So
![s = \frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![2.8 = \frac{8.4}{\sqrt{n}}](https://tex.z-dn.net/?f=2.8%20%3D%20%5Cfrac%7B8.4%7D%7B%5Csqrt%7Bn%7D%7D)
![2.8\sqrt{n} = 8.4](https://tex.z-dn.net/?f=2.8%5Csqrt%7Bn%7D%20%3D%208.4)
![\sqrt{n} = \frac{8.4}{2.8}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B8.4%7D%7B2.8%7D)
![\sqrt{n} = 3](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%203)
![(\sqrt{n})^2 = 3^2](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E2%20%3D%203%5E2)
![n = 9](https://tex.z-dn.net/?f=n%20%3D%209)
Answer:
Total distance:
- d=11/15 miles or 0.73 miles
Step-by-step explanation:
- Alison walks 2/5 miles from her house to the mailbox.
- Then she walks 1/3 mile to the bus stop.
Thus, the total distance can be calculated by adding the miles
i.e.
![d=\:\frac{2}{5}+\frac{1}{3}](https://tex.z-dn.net/?f=d%3D%5C%3A%5Cfrac%7B2%7D%7B5%7D%2B%5Cfrac%7B1%7D%7B3%7D)
LCM of 5,3 is 15
![=\frac{6}{15}+\frac{5}{15}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B6%7D%7B15%7D%2B%5Cfrac%7B5%7D%7B15%7D)
![\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Athe%5C%3Afraction%5C%3Arule%7D%3A%5Cquad%20%5Cfrac%7Ba%7D%7Bc%7D%2B%5Cfrac%7Bb%7D%7Bc%7D%3D%5Cfrac%7Ba%2Bb%7D%7Bc%7D)
![=\frac{11}{15}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B11%7D%7B15%7D)
miles
Thus,
Total distance:
- d=11/15 miles or 0.73 miles