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kaheart [24]
3 years ago
10

Suppose that a box contains 7 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without repl

acement. Define the random variable
X
as the number of defective cameras in the sample.
Mathematics
1 answer:
irinina [24]3 years ago
8 0

Answer:

E(x) = 1.43 (Approx)

Step-by-step explanation:

Given:

Total number of camera = 7

Defective camera = 5

Sample selected = 2

Computation:

when x = 0

P(x=0) = 2/7 × 1/6 = 2/42

P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42

P(x=2) = 5/7 × 4/6 = 20/42

So,

E(x) = [0×2/42] + [1×20/42] + [2×20/42]

E(x) = 1.43 (Approx)

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-1.023 + 5.6 (show how you got the answer)
Rom4ik [11]

Answer:

-1.023 + 5.6 = 4.58

Step-by-step explanation:

1. Drop the 3 in -1.023, becoming -1.02

2. Add 0 at the end of 5.6, becoming 5.60

3. Here is the problem you now solve:

   -1.02 + 5.60. You can simply type this into your calculator. I hope this helped.

4 0
3 years ago
Read 2 more answers
Find the common difference in the outputs to help find the missing outputs in the table
WINSTONCH [101]

Answer:

if you are trying to find the rest of A it would be adding by 1 because of the slope so: 5,6,7,8,9,10. The slope of B wouldbe .8 because it is increasing by .8 everytime so: 3.8,4.6,5.4,6.2,7.0

Step-by-step explanation:

B) 4.6-3.8= .8

5.4-4.6= .8

slope is .8

5.4+.8=6.2

6.2+ .8= 7.0


8 0
3 years ago
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The radius of a circle can be found by dividing the circumference of the circle by 6.28. What is the radius of a circle that has
steposvetlana [31]
The radius of a circle is found by doing this :
circumference ÷ 6.28 = radius

The circumference here is 17.27 feet :
circumference ÷ 6.28 = radius
so
17.27 ÷ 6.28 = 2.75


The radius of the circle is 2.75 feet.






5 0
3 years ago
Similar statement of √111<br> Pls help
Diano4ka-milaya [45]
111 is between 11 and 12
7 0
3 years ago
Prove that DJKL~ DJMN using SAS Similarity Theorem. Plot the points J (1,1), K(2,3), L(4,1) and J (1,1), M(3,5), N(7,1). Draw DJ
dolphi86 [110]

Answer and Step-by-step explanation: The triangles are plotted and shown in the attachment.

SAS Similarity Theorem is by definition: if two sides in one triangle are proportional to two sides of another triangle and the angles formed by those sides in each triangle is congruent, the triangles are similar.

For the triangles on the grid, we know that ΔJKL and ΔJMN have a congruent angle in J as shown in the image. To prove they are similar, we find the slope of sides KL and MN:

<u>Slope of KL</u>:

slope = \frac{y_{K} - y_{L}  }{x_{K} - x_{L} }

slope = \frac{3-1}{2-4}

slope = -1

<u>Slope of MN</u>:

slope = \frac{y_{N} - y_{M}  }{x_{N} - x_{M} }

slope = \frac{1-5}{7-3}

slope = -1

Since the slopes of KL and MN are the <u>same</u> and the angle is <u>congruent</u>, we can conclude that ΔJKL~ΔJMN.

5 0
3 years ago
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