Question

Match each quadratic function given in factored form with its equivalent standard form listed on the left. f(x) = (x + 2)(x – 6) f(x) = (x – 4)(x + 3) f(x) = (x – 12)(x + 1) f(x) = (x – 3)(x + 4)

Answer 1

Step-by-step explanation:

Write the standard form for the given factored form of quadratic functions

f(x) = (x + 2)(x – 6)

to get standard form we multiply the parenthesis using FOIL method

$f(x)=(x + 2)(x – 6)= x^2 -6x+2x-12= x^2-4x-12$

f(x) = (x – 4)(x + 3)

$f(x)=(x – 4)(x + 3)= x^2 +3x-4x-12= x^2-x-12$

f(x) = (x – 12)(x + 1)

$f(x)= (x – 12)(x + 1)=(x^2 +1x-12x-12= x^2-11x-12$

f(x) = (x – 3)(x + 4)

$f(x)=(x – 3)(x + 4)= x^2 +4x-3x-12= x^2+x-12$

Answer 2

Expand the brackets to obtain your answers:
1. f(x)=x²-4x-12
2. f(x)=x²-x-12
3. f(x)=x² -11x-12
4. f(x)=x²+x-12