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eimsori [14]
3 years ago
9

10. How can we tell if a number is divisible by 4?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0
If the number formed by two last digits of a number is divisible by 4, then a number is divisible by 4 as well.
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The value of 9 there is 90 since it is in the tens place.
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9. The diagram below shows a plan for a park. ABCD is a rectangle. APB and DQC are semicircles
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HELP ME PLZ!!!!!! Which values equivalent to the fraction below? CHECK ALL THAT APPLY.
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Using the slope and the y-intercept graph the line represents by the following equation then select the correct graph 2y + 4 =0
dybincka [34]

Answer:

Step-by-step explanation:

2y + 4 = 0               <em>subtract 4 from both sides</em>

2y = -4       <em>divide both sides by 2</em>

y = -2

The slope-intercept form of an equation of a line:

y = mx + b

m<em> - slope</em>

b<em> - y-intercept → (0, </em><em>b</em><em>)</em>

In the equation

y = -2

<em>slope: </em><em>m = 0</em>

<em>y-intercept: </em><em>b = -2 → (0, -2)</em>

<em />

<em>y = -2 - it's a horizontal line</em>

8 0
3 years ago
Explain and demonstrate the multiplication of complex conjugates using 2+3i and its complex conjugate. Be sure to discuss all st
krok68 [10]

The product of a <em>complex</em> number and its conjugate is (a + i b) · (a - i b), where a and b are <em>real</em> numbers, and the result for the <em>complex</em> number 2 + i 3 is 13.

<h3>What is the multiplication of a complex number and its conjugate</h3>

Let be a <em>complex</em> number a + i b, whose conjugate is a - i b. Where a and b are <em>real</em> numbers. The product of these two numbers is:

(a + i b) · (a - i b)

Then, we proceed to obtain the result by some algebraic handling:

a · (a + i b) + (- i b) · (a + i b)

a² + i a · b - i a · b - i² b²

a² - i² b²

a² + b²

If we know that a = 2 and b = 3, then the product of the complex number and its conjugate is:

z\cdot \bar z = 2^{2} + 3^{2}

z\cdot \bar z = 13

To learn more on complex numbers: brainly.com/question/10251853

#SPJ1

6 0
2 years ago
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