Now we see that in order to remove 56 and only be left with 1x on leftside we have to multipley by 56. If we do so on on side we have to do on the other side. So both sides multiplies by 56
so you multiply 5 and 9 which is 45- 10 which is 35 but then its 5-(-2) which when doing this a variable minus a negative makes it a positive so then its 5+2 which is 7 then you have 35/7 or 5