The complete question in the attached figure
we know that
area each pasture=15000 ft²
area each pasture=x*y
so
15000=x*y-----> equation 1
perimeter two rectangular pastures=1050 ft
perimeter two rectangular pastures=2*[2x+y]+y----> 4x+2y+y---> 4x+3y
so
1050=4x+3y----> divide by 3----> 1050/3=(4/3)x+y
clear variable y
y=350-(4/3)x-----> equation 2
the answer part a) y=350-(4/3)x------> <span>
it was proved</span>
Part b)Find the possible lengths and widths of each pasture.
substitute equation 2 in equation 1
15000=x*y-----> 15000=x*[350-(4/3)x]
15000=350x-(4/3)x²----> multiply by 3----> 45000=1050x-4x²
4x²-1050x+45000=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=53.942 ft
x=208.558 ft
15000=x*y-----> y=15000/x
for x=53.94 ft
y=278.09 ft
for x=208.56 ft
y=71.92 ft
the possible lengths and widths of each pasture are
case 1
x=53.94 ft
y=278.09 ft
case 2
x=208.56 ft
y=71.92 ft
Answer:
6
Step-by-step explanation:
First you want to rewrite the equation
2*1-3*(-1)+1
Then you want to do order of operations until you get your answer!
I hope this helps!
Answer:the mean is greater than the median
Step-by-step explanation:
Answer:
ur answer would be 64
Step-by-step explanation:
length is 32
width is 64
Current volume = 10 glns
Miles he can drive currently = 28miles/ gln * 10= 280miles
Cost of gas= 1.40/gln
Function= s /1.40 *28 +280= 28s/1.40 +280=20s + 280
Final answer would be 20s + 280