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alexira [117]
3 years ago
13

The Red Line in the figure is an altitude of triangle hjl. Using right angle trig and properties of equality, y sin L = x = z si

n H, write the Law of Sines for this triangle
​

Mathematics
2 answers:
aivan3 [116]3 years ago
7 0

Answer:

\Large \boxed{\mathrm{\bold{C}}}

Step-by-step explanation:

\sf \displaystyle sin(\theta) =\frac{opposite}{hypotenuse }

\sf \displaystyle sin(L) =\frac{x}{y}

\sf \displaystyle sin(H) =\frac{x}{z}

\displaystyle \sf \frac{sinL}{z} =\frac{sinH  }{y}

\displaystyle \sf \frac{\frac{x}{y} }{z} =\frac{\frac{x}{z} }{y}

Simplifying the expression.

\sf \displaystyle \frac{x}{yz } = \frac{x}{yz} \ (true)

\displaystyle \sf \frac{z}{sinL} =\frac{y}{sinH}

\displaystyle \sf \frac{z}{\frac{x}{y}} =\frac{y}{\frac{x}{z}}

Multiplying both sides by x.

\sf yz=yz  \ (true)

Alexxx [7]3 years ago
5 0

Answer:

d

Step-by-step explanation:

The law of Sines applied to a Δ ABC is

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

Using this in Δ HJL

\frac{z}{sinL} = \frac{y}{sinH} → (b)

Which may be expressed in reciprocal form as

\frac{sinL}{z} = \frac{sinH}{y} → (a)

Thus the law of Sines can be expressed as either (a) or (b)

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