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gogolik [260]
4 years ago
6

The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than av

erage quality. His research shows that replacement times for the model laptop of concern are normally distributed with a mean of 4.3 years and a standard deviation of 0.4 years. He then randomly selects records on 27 laptops sold in the past and finds that the mean replacement time is 4.1 years.
Assuming that the laptop replacment times have a mean of 4.5 years and a standard deviation of 0.5 years, find the probability that 32 randomly selected laptops will have a mean replacment time of 4.3 years or less.
P(M < 4.3 years) =
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Based on the result above, does it appear that the computer store has been given laptops of lower than average quality?
Mathematics
1 answer:
myrzilka [38]4 years ago
6 0

Answer:

P(z ≤ -2.263) = 0.012 ( 3 dp)

Yes,  the computer store has been given laptops of lower than average quality. The probability is unlikely to have occurred by chance.

Step-by-step explanation:

Sample size, n = 32

Mean, \mu = 4.5

Standard deviation, \sigma = 0.5

Sample mean, M = 4.3

z = \frac{M - \mu}{\sigma / \sqrt{n} } \\z = \frac{4.3 - 4.5}{0.5 / \sqrt{32} }

z = - 2.263

Probability that the selected laptops will have a mean replacement time of 4.3 years or less.

P(M ≤ 4.3 years) = P(z ≤ -2.263)

P(z ≤ -2.263) = 0.0118

P(z ≤ -2.263) = 0.012 ( 3 dp)

P(z ≤ -2.263) = 0.012 is less than 0.05 significant level, it is safe to conclude that the computer store has been given laptops of lower than average quality

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Answer:

\textsf{a.} \quad \overleftrightarrow{AV} \; \textsf{and} \; \overleftrightarrow{RV}

\textsf{b.} \quad STZ, \; RTZ, \;QTZ

\textsf{c.} \quad A, R\; \textsf{and}\; V

\textsf{d.} \quad Q,S,T \; \textsf{and}\; Z

\textsf{e.} \quad \overline{AR}

\textsf{f.} \quad \overrightarrow{RA} \; \textsf{and} \; \overrightarrow{RV}

Step-by-step explanation:

<h3><u>Part a</u></h3>

A line can be named by using two points on the line or by a (lowercase) letter.

Therefore, two other names for line p are:

  • \overleftrightarrow{AV}
  • \overleftrightarrow{RV}

<h3><u>Part b</u></h3>

A plane can be named by using three non-collinear points in the plane or by a (capital script) letter.

Therefore, three other names for plane <em>W</em> are:

  • STZ
  • RTZ
  • QTZ

<h3><u>Part c</u></h3>

Collinear points are points that lie on the same line.

The collinear points on the given diagram are: A, R & V, and S, R & Q.

Therefore, three points that are collinear are:

  • A, R and V

<h3><u>Part d</u></h3>

Coplanar points are <u>three or more points</u> that lie in the same plane.

The coplanar points on the given diagram are: Q, R, S, T and Z

Therefore, four points that are coplanar are:

  • Q, S, T and Z

<h3><u>Part e</u></h3>

A line segment is part of a line that has two endpoints, and is named by its two endpoints.

The line segments on the given diagram are:

\overline{AR}, \;\overline{RV}, \; \overline{AV}, \; \overline{SR}, \; \overline{RQ} \; \textsf{and}\; \overline{SQ}.

Therefore, a line segment is:

  • \overline{AR}

<h3><u>Part f</u></h3>

A ray is a part of a line that has one endpoint (so continues infinitely in the direction without an endpoint).  

Opposite rays are two rays that have a common endpoint and form a line.  They are named by the common endpoint followed by any other point on each ray.

The pairs of opposite rays on the given diagram are:

\overrightarrow{RA} \; \textsf{and} \; \overrightarrow{RV}, \quad \overrightarrow{RS} \; \textsf{and} \; \overrightarrow{RQ}

Therefore, a pair of opposite rays are:

  • \overrightarrow{RA} \; \textsf{and} \; \overrightarrow{RV}
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