Answer:
The probability of the chosen ball being shiny conditional on it being red is; 0.375
Step-by-step explanation:
Let A be the event that a red ball has been chosen
Let B be the event that a shiny ball has been chosen
Let S be the total outcomes = 150 balls
Thus;
P(A ∩ B ) = 36/150
A ∩ B' = 150 - 36 - 54
A ∩ B' = 60
Thus; P(A ∩ B') = 60/150
P(A') = 54/150
P(A) = (150 - 54)/150 = 96/150
Thus, probability of the chosen ball being shiny conditional on it being red is;
P(B | A) = P(B ∩ A)/P(A)
Thus; P(B | A) = (36/150)/(96/150)
P(B | A) = 0.375
Answer:
i dont know it srry
Step-by-step explanation:
To factor, we always have to look for common factors in the numbers given to us. In this case, in 1/2 and 6, the common factor is 1/2. Therefore, we will have to factor like so:
1/2d + 6 = 1/2 (d + 3)
Hope this helps!
To solve this problem you must follow the proccedure shown below:
1. Amount of lemonade in pints:
1 <span>quart of water=2 pints
1 pint of lemon
(9 ounces of honey)(0.0625 pints/1 ounce)=0.56 pints
Total in pints=2 pints+1 pint+0.56 pints
Total in pints=3.56 pints
2. </span>Amount of lemonade in<span> cups:
Total in cups=(3.56 pints)(2 cups/1 pint)
Total in cups=7.12 cups
3. </span>Amount of lemonade in<span> ounces:
Total in ounces=(7.12 cups)(8 ounces/1 cup)
Total in ounces=56.96 ounces</span>
