Question

Consider the diagram. Which line segment has the same measure as ST?

Answer 1

SR because any point on a perpendicular bisecting line is equidistant from the ends of the bisected segment.

Answer 2

Answer:

$SR$

Step-by-step explanation:

In this problem we have

$RX=XT$ -----> given problem

$XS$ ---> is a common side both triangles

In the right triangle RSX

Applying the Pythagoras Theorem

$SR^{2}=RX^{2}+XS^{2}$ ------> equation A

In the right triangle XST

Applying the Pythagoras Theorem

$ST^{2}=XT^{2}+XS^{2}$ ------> equation B

remember that -----> $RX=XT$

Substitute

$ST^{2}=RX^{2}+XS^{2}$ ------> equation C

Compare equation A and equation C

$SR=ST$