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cluponka [151]
3 years ago
7

Consider the diagram. Which line segment has the same measure as ST?

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0
SR because any point on a perpendicular bisecting line is equidistant from the ends of the bisected segment.
Yanka [14]3 years ago
7 0

Answer:

SR

Step-by-step explanation:

In this problem we have

RX=XT -----> given problem

XS ---> is a common side both triangles

In the right triangle RSX

Applying the Pythagoras Theorem

SR^{2}=RX^{2}+XS^{2} ------> equation A

In the right triangle XST

Applying the Pythagoras Theorem

ST^{2}=XT^{2}+XS^{2} ------> equation B

remember that -----> RX=XT

Substitute

ST^{2}=RX^{2}+XS^{2} ------> equation C

Compare equation A and equation C

SR=ST

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2/3 divide by 4/5? ​
Alenkasestr [34]

Answer:

\frac{5}{6}

Step-by-step explanation:

  \frac{2}{3}                ÷                 \frac{4}{5}

  ↓               ↓                 ↓  

leave it   change it   turn it over

  \frac{2}{3}                ×                  \frac{5}{4}

now solve it

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3 years ago
A contractor is building a fence around a square garden that has a side length of 3 inches in a
Pavel [41]

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7 0
2 years ago
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

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4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

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4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

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6 0
3 years ago
If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI
Vikentia [17]

Answer:

The value is      y  =  \$ 225

Step-by-step explanation:

From the question we are told that

   The amount charge per year is  k  =  \$ 200

   The  number of members it will have at this amount is  n  =  50

   The amount amount increase that will lead to the loss of a single member is   z =  \$ 5

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Thus the number of members that be removed to  give the maximum  income from dues is obtained by differentiating the above equation and equating it to zero

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So from  I  =  (200 + 5x) (50-x ) we have

          I  =  (200 + 5 (5)) (50-5 )

           I  = \$ 10125

So the amount the club should charge is    

         y  =  \frac{10125}{50 - 5}

         y  =  \$ 225

         

7 0
4 years ago
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