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3 years ago

Consider the diagram. Which line segment has the same measure as ST?

Mathematics

2 answers:

valentinak56 [21]3 years ago

8 0

SR because any point on a perpendicular bisecting line is equidistant from the ends of the bisected segment.

Yanka [14]3 years ago

7 0

Answer:

$SR$

Step-by-step explanation:

In this problem we have

$RX=XT$ -----> given problem

$XS$ ---> is a common side both triangles

In the right triangle RSX

Applying the Pythagoras Theorem

$SR^{2}=RX^{2}+XS^{2}$ ------> equation A

In the right triangle XST

Applying the Pythagoras Theorem

$ST^{2}=XT^{2}+XS^{2}$ ------> equation B

remember that -----> $RX=XT$

Substitute

$ST^{2}=RX^{2}+XS^{2}$ ------> equation C

Compare equation A and equation C

$SR=ST$

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How many solutions does this equation have?

kozerog [31]

Hello from MrBillDoesMath!

Answer: infinite solutions

Discussion: I did a double take on this one but the left hand is

a + 3 + 2a = 3a +3

and the right hand side is

-1 + 3a + 4 = 3a + (4-1) = 3a + 3

The left and right sides of the equation are identical for all "a", i.e. for infinitely many "a" values.

Regards, MrB.

5 0

3 years ago

Read 2 more answers

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$

<h3>Hence the area of the shaded region is 264 cm².</h3>

5 0

3 years ago

The URS construction company has submitted two bids, one to build a large hotel in London and the other to build a commercial o

topjm [15]

Answer: Our required probability is 0.55.

Step-by-step explanation:

Since we have given that

Probability that chance of winning the hotel bid = 40%

Probability that no chance of winning the hotel bid = 100-40=60%

Probability that chance of winning the office building bid = 25%

Probability that no chance of winning the office building bid = 100-25 = 75%

So, Probability that the company will win at least one contract is given by

$0.4\times 0.75+0.6\times 0.25+0.4\times 0.25\\\\=0.55$

Hence, our required probability is 0.55.

5 0

3 years ago

A nonprofit organization sent mailing labels along with a request for donations to a random sample of 75,000 potential donors on

Law Incorporation [45]

Answer:

Check the explanation

Step-by-step explanation:

The null and alternative hypotheses in symbols and words are as follows:

: p ≤ 0.06 (There has been no change in the contribution rate due to addition of the mailing labels)

: p > 0.06 (The addition of the mailing labels has increased the contribution rate)

Test Statistics

The following information is provided: The sample size is N = 75000, the number of favorable cases is X = 5625, and the sample

The z-statistic is computed as follows:

- $P_0$ (1 -

Test statistic z = 17.297

P-value

P-value corresponding to z = 17.297 for a two tailed test is obtained using standard normal table.

p-value = 0.0000

90% Confidence Interval Calculation

Kindly check the attached image below.

Conclusion

Since p-value = 0.0000 < α = 0.05, we reject null hypothesis .

At 0.05 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

Since the 90% confidence interval (0.073, 0.077) does not contain the hypothesized value 0.06, the result is significant and we reject null hypothesis.

In other words, at 0.10 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

4 0

3 years ago

-8x times 5 to the power of 3 would equal -1000x right?

marusya05 [52]

No. If you write it out, it would be -8*5 which is -40. (-40)^3 is -64000. So your answer would be -64000x

4 0

3 years ago