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2 years ago

Consider the diagram. Which line segment has the same measure as ST?

Mathematics

2 answers:

valentinak56 [21]2 years ago

8 0

SR because any point on a perpendicular bisecting line is equidistant from the ends of the bisected segment.

Yanka [14]2 years ago

7 0

Answer:

$SR$

Step-by-step explanation:

In this problem we have

$RX=XT$ -----> given problem

$XS$ ---> is a common side both triangles

In the right triangle RSX

Applying the Pythagoras Theorem

$SR^{2}=RX^{2}+XS^{2}$ ------> equation A

In the right triangle XST

Applying the Pythagoras Theorem

$ST^{2}=XT^{2}+XS^{2}$ ------> equation B

remember that -----> $RX=XT$

Substitute

$ST^{2}=RX^{2}+XS^{2}$ ------> equation C

Compare equation A and equation C

$SR=ST$

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It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe

lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u $\frac{km}{hr}$

Speed of current = v $\frac{km}{hr}$

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

$32 = \frac{100}{u +v}$

$u + v = \frac{100}{32}$

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

$48 = \frac{100}{u -v}$

$u -v = \frac{100}{48}$

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 $\frac{km}{hr}$

v = 0.5205 $\frac{km}{hr}$

Now the time taken by the un powered raft to cover this distance

$T = \frac{100}{v}$

Because un powered raft travel with the speed of the current.

$T = \frac{100}{0.5205}$

T = 192.12 hr

Therefore the time taken by the un powered raft to cover this distance is

T = 192.12 hr

3 0

2 years ago

Read 2 more answers

Solve for x and graph the solution on the number line 15 > 2x – 9 > -23

Monica [59]

The answer is 12>x>-7

Step-by-step explanation:

it's first divided into 2 parts

1 . 15 > 2x - 9

2. 2x - 9 > -23

Then solve them individually.

let's do it,

First half

15 > 2x - 9

15+9 > 2x

24 > 2x

24/2 > x

12>x

Second half

2x-9>-23

2x>-23+9

2x>-14

x>-14/2

x>-7

Joining of the two halves

We have :

12>x>-7

8 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

Read 2 more answers

During one waiter’s shift, he delivered 13 appetizers, 17 entrées, and 10 desserts.

Romashka-Z-Leto [24]

Answer:

whats the question

Step-by-step explanation:

will be edited when answered

5 0

2 years ago

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In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t

ra1l [238]

Answer:

it's A

Step-by-step explanation:

Just took the assignment on EDG

7 0

2 years ago