The product<span> of </span>two consecutive negative integers<span> is 462. Determine the two </span>integers<span>. ... Since this is a quadratic equation, we'll </span>get<span> one side equal to zero (by subtracting 462 from each side): ... Since </span>20*20<span> = 400 we can start near there.</span>
set f(x) equal to y
y = 19/ x^3
swap x and y
x = 19/y^3
make y the subject
xy^3 = 19
y^3 = 19/x
![y = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
then just replace y with f^-1(x)
![f(x) = \sqrt[3]{ \frac{19}{x} }](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B19%7D%7Bx%7D%20%7D%20)
hope this helped! have a good day ~ •lipika•
Answer:
huh
Step-by-step explanation:
did you add anything?
Step-by-step explanation:


<h3>#CMIIW</h3>
Answer:
-√2
Step-by-step explanation:
For the typing purpose I replaced θ with n in the calculation
