Question

The sum of two numbers is 37. The greater number is 5 more than three times the lesser number. What is the lesser of the two numbers?

Answer 1

Answer: Lesser number is 8

Step-by-step explanation:

Let the smaller number be y.

Greater number= (3×y)+ 5 = 3y+5

y+3y+5 = 37

4y + 5 = 37

4y= 37-5

4y=32

y=8

Smaller number is 8

Bigger number is 3y+5= (3×8)+5 = 29

Answer 2

Answer:

The lesser of the two numbers is 8.

Step-by-step explanation:

Let the greater number be $x$ and lesser number be $y$.

We are given with following conditions;

• First condition says that the sum of two numbers is 37, i.e;

                              $x+y=37$

                                $x=37-y$  -------------- [Equation 1]

• Second condition says that the greater number is 5 more than three times the lesser number, i.e;

                              $x=5+3y$

                           $37-y=5+3y$  {using equation 1}

                           $3y+y=37-5$

                                $4y = 32$

                                  $y=\frac{32}{4}$ = 8

Therefore, the lesser of two numbers, $y$ = 8.