Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
The perimeter would be ≈ 36.797836892947.
Rounded would be about 37, or 36.8.
Hope this helps!!!!


Solving for P:
≈36.79784
Hope this helps!!
Answer:
4
Step-by-step explanation:
9×3=27
2×7=14
1×4=4
nice logic
Answer: The value of x is 7
Step-by-step explanation: