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ziro4ka [17]
2 years ago
6

True false are these triangles congruent?

Mathematics
2 answers:
Hunter-Best [27]2 years ago
7 0
True they have same sides
Vanyuwa [196]2 years ago
6 0
They are congruent:)<span />
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Four congruent isosceles right triangles are cut from the 4 corners of a square with a side of 20 units. The length of one leg o
yanalaym [24]

Answer:

368 sq. units.

Step-by-step explanation:

We have a square of side lengths 20 units and we cut four congruent isosceles right triangles from the corners of the square.

Now, the four isosceles right triangles have one leg equal to 4 units.  

Therefore, the area of four triangles = 4 \times ( \frac{1}{2} \times 4 \times 4) = 32 sq. units.

Now, we have the area of the given square is (20 × 20) = 400 sq. units.

Therefore, the area of the remaining octagon will be (400 - 32) = 368 sq. units. (Answer)

7 0
3 years ago
Find the value of z in the figure below.<br>.​
zzz [600]

answer

z = 100

opposite angles

when inscribed in a circle, the opposite angles of a quadrilateral add up to 180

so z + 80 = 180 and y + 120 = 180

solve for z

z + 80 = 180

z = 180 - 80

z = 100

3 0
3 years ago
Estimate the quotients 3.53/51 =
ale4655 [162]
An accurate estimate is anywhere from 0.06 to 0.07. The exact answer is 0.06921568627.
3 0
3 years ago
How do u make 3/4 in a mix number as a whole number or decimal?
KengaRu [80]
In decimal form it's .75 and that's all you can make it
7 0
2 years ago
A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,
Romashka-Z-Leto [24]

Answer:

radius   x  = 3 ft

height   h = 23,8  ft

Step-by-step explanation:

From problem statement

V(t)  = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c)  = π*x²*h       area of cylinder = area of base + lateral area

                                              A(c)  = π*x²  +   2*π*x*h

V(h) = (2/3)*π*x³   area of hemisphere   A(h)  =   (2/3)*π*x²

A(t)  =  π*x²  +   2*π*x*h +   (2/3)*π*x²

Now A as fuction of x    

total volume   505  = π*x²*h  +  (2/3)*π*x³

h = [505 - (2/3)* π*x³ ]  /2* π*x    

Now we have the expression for A as function of x

A(x) =  3π*x² + 2π*x*h     A(x) = 3π*x² + 505  - (2/3)π*x³

Taking derivatives both sides

A´(x) =  6πx -  2πx²              A´(x) =  0         6x  - 2x²  = 0

x₁  =  0  we dismiss

6 - 2x = 0

x = 3     and   h = [505 - (2/3)* π*x³]/2* π*x

h  =  (505 - 18.84) / 6.28*3

h  = 23,8  ft

7 0
3 years ago
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