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3 years ago

There are 25 students in a class. 2525 of them walk to school.

2 answers:

6 0

Even IF you meant 25/25, I don't understand what you mean by which method. Could you please clarify? Comment on my answer, and I will comment you your answer.

Yanka [14]3 years ago

3 0

You would have to do 25/25 to get the answer

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Solve the equation. 4x + 1 + 2x = 61 6 10 10.3 11.8

poizon [28]

Answer:

x = 10

Step-by-step explanation:

=> 4x + 1 + 2x = 61

=> 6x = 61 - 1

=> 6x = 60

=> x = 60/6

=> x = 10

Hence the value of x is 10 .

3 0

2 years ago

As a member of a music you can order CDs for $14.99 each the music club also charges $4.99 for shipment the expression 14.99n+4.

aksik [14]

14.99n+4.99 represents the cost of n cds
(14.99x3) + 4.99 =
34. 97 + 4.99= $39.97- 0.1= $39.96
3 CD s cost $39.96

5 0

2 years ago

Solve the following question

White raven [17]

Answer:

g) $u^{4}\cdot v^{-1}\cdot z^{3}$ , h) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$

1) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$ Given

2) $\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }$ Definition of division

3) $\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)$ Associative property

5) $u^{4}\cdot v^{-1}\cdot z^{3}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ /Result

h) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$

1) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$ Given

2) $\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }$ Definition of division

3) $\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }$ Factorization/Distributive property

5) $\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right]$ Modulative and commutative properties/Associative property

6) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ / $\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}$ /Definition of division/Result

3 0

2 years ago

Write down the coordinates of the image of the point (2-3) under reflecting about the line joining the points (3, 5) and (3,7)

Murrr4er [49]

Answer:

(4 , -3)

Step-by-step explanation:

the points (3 , 5) and (3 , 7) have the same x-coordinates 3

then ,the line D joining them has the equation

D : x = 3

the image of the point A(2 , -3) under reflecting about The line D ,

lie on the line ∆ perpendicular to D and passes through A.

∆ perpendicular to D then the equation of ∆ is :

∆ : y = a ,where a is a real number.

Calculating ‘a’ :

∆ passes through A

Then

-3 = a

Therefore

the final equation of ∆ is :

∆ : y = -3

Obviously, the lines D and ∆ intersect at the point M(3 , -3)

FINAL STEP :

Calculating the coordinates of the point B(x , y) image of the point A(2 , -3)

M is the midpoint of the line segment AB :

Then

3 = (2 + x)/2 and -3 = (-3 + y)/2

Then

x = 4 and y = -3.

4 0

2 years ago

When evaluating (6x+3)2 -5 for x= 1, the given value of 1 is substituted for what part of the expression?

aev [14]

Answer:

variable

Step-by-step explanation:

the variable

(6× + 3) means (6×1 + 3)

x is a variable

6 0

3 years ago