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EastWind [94]
3 years ago
7

Prove: △VWZ ≅ △YWZ

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:


Step-by-step explanation:

Statements                          Reasons

----------------------------------------------------------------

1. ∠V ≅ ∠Y                        Given

2. WZ bisects ∠VWY          Given

3. ∠VWZ ≅ ∠YWZ            Definition of Angle Bisector (2)

4. WZ ≅ WZ                         Reflexive Property

5. ΔVWZ ≅ ΔYWZ               AAS Theorem (1,3,4)

**In case you didn't know the definitions**

Angle Bisector - A line, segment or ray that divides an angle into two congruent angles

Reflexive Property - X = X

AAS Postulate -  If two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangle's are congruent

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Answer:

LM+MN=LN

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4x=17+5-7

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x=15/4=3.75

LM= 3x-5=3*3.75-5=6.25

Step-by-step explanation:

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3 years ago
Aakesh has two bags of marbles. The first bag contains 6 red marbles, 4 blue
Orlov [11]

The answer for the 1st bag is option B = 1/3

The answer for the 2nd bag is option C = 5/9

Number of marbles in 1st bag - 15 (6 red, 4 blue & 5 green)

Number of marbles in 2nd bag - 9 (3 red, 1 blue & 5 green)

The formula of probability = Total number of events in the outcome /total number of outcomes.

Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)

That is 5/15=1/3

Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)

That is 5/9

To know more about probability go to -  https://brainly.in/question/17157610?msp_poc_exp=6

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2 years ago
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What is the measure of space inside a suitcase?
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Step-by-step explanation:

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4 0
2 years ago
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what is the length of the longest side of a triangle that has the vertices (2, 6), (-4, 6), and (-4, 4)? a. 2/10 units b. 40 uni
rewona [7]
Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40)  = 2sqrt(10) units

Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2

Therefore, the length of the longest side is 2sqrt(10) units
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3 years ago
Find the distance between the points (-8,-11) and (14,-11).​
coldgirl [10]

Answer:

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Step-by-step explanation:

The answer is provided above.

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Hope this helps.

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