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Daniel [21]
3 years ago
12

Give one example of when you would make a frequency table to solve the problem

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

Consider a class in which there are 40 students .There is a Mathematics test of 50 marks .Two students were absent.The Duration of test was for one and half an hour.

So Marks of students according to their roll number are 12,8,4,20,25,36,2,29,35,39,5,48,43,37,38,29,17,15,15,25,31,32,26,28,27,24,2,15,34,,50,46,48,37,28,26,45,49,24.

So in this case it would be better to prepare frequency polygon by selecting a class interval.

Class interval = 0-5,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45,45-50.

Or 0-10,10-20,20-30,30-40,40-50.

or you can make class interval by yourself.





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Please help me with this i will give brainliest
dmitriy555 [2]

Answer:

the first one and the last one,

Step-by-step explanation:

I took the test :) hope you pass

8 0
2 years ago
What's 8,936.25 to the nearest hundred? please help​
klemol [59]

Answer:

9,000.

Step-by-step explanation:

Since the hundreds column contains a 9, we need to move to the thousands column and add 1. When doing this you do not need to include the rest of the numbers. (Just replace them with zeros.)

Hope that helps. x

5 0
2 years ago
Max ran two miles each day for 4days. Then he ran 3 miles each day for the next 4 days. How many miles did Max run altogether in
svp [43]
4 days • 2 miles = 8 miles
4 days • 3 miles = 12 miles
8 miles + 12 miles = 20 miles in total for all 8 days
8 0
3 years ago
3x-1/5=x+1/3 pls help me
RoseWind [281]

Answer:

x=4/15

Step-by-step explanation:

first you need to make common denominators for 1/5 and 1/3

the common denominator is 15

5*3=15, 3*5=15. 1*3=3, 1*5=5

new equation:3x-3/15=x+5/15

now subtract x from both sides: 3x-3/15=x+5/15

                                                     -x          -x

                                                     2x-3/15=5/15

now you can add 3/15 to 5/15

2x=8/15

now for the last step, divide by 2 because there are 2 x's

2x/2=x         8/15 /2=4/15

x=4/15

8 0
11 months ago
Read 2 more answers
How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
lidiya [134]

Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

Solution:

Here we are given with the sides of the triangle as 5m, 16m and 5.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.

Hence no triangle can be made.

So the correct option is None.

Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?

Solution:

Here we are given with the sides of the triangle as 6m, 2m and 7m.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.

Hence one triangle can be formed.

So the correct option is  one.

8 0
3 years ago
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