Solving for y, we add 5y to both sides and subtract 4, getting 9x-4=5y. Dividing both sides by 5, we get 9x/5-4/5=y. Since the slope is 9/5 (since 9/5*x=9x/5), we multiply it by -1 and find the reciprocal of it to get -5/9 as the perpendicular slope, so -5x/9+b=y. Plugging 1 in for x and -6 in for y, we get -5*1/9+b=-6 and by adding 5/9 to both sides we get -5-4/9=b , and since in y=mx+b y and x are variables, we end up with y=-5x/9+(-5-4/9) for slope intercept form.
To get it into standard form, we need it in ay+cx=b with a, b, and c being constants. Adding 5x/9 to both sides, we end up with y+5x/9=(-5-4/9) for standard form
What do I need to solve :)
Answer:
a) Interquartile range= upper quartile- lowwr quartile
= Q3- Q1
= 4.75-2.25
= 2.50
b) ( 2.5 ÷ 6 ) × 100
= 41.67%
42300 / 10 = 4230
4230 * 500 = 2115000
a number multiplied by ten equals to 42300, so 10a = 42300, then a = 4230, then you multiply 4230 and 500 together, which gives you 2115000
Just answered this one a few minutes ago.
(-5)(-5)(3)= 75
