Martin is studying sucrase activity. He added sucrose solution + sucrase solution + buffer of pH 5.6 in two tubes. He incubated
them at 350C and 1000C respectively. When he performed a confirmatory test, only the first test tube showed enzyme activity. How would you justify the inactivity of the enzyme in the second test tube? The enzymes in the second test tube must have denatured at pH 5.6, since most enzymes work at neutral pH.
The enzymes in the second test tube must have denatured at 1000C, since most enzymes degrade at such high temperatures.
Enzymes must have remained dormant at 1000C, since most of the enzymes remain inactive at such higher temperatures.
The correct answer is "The enzymes in the second test tube must have denatured at 1000C, since most enzymes degrade at such high temperatures".
Explanation:
Most enzymes are purified or produced from amino acid sequences found in nature. Since most organisms live in mild temperature conditions, enzymes are active under mild temperature conditions. This is the case of sucrase, which has activity at 35 celsius but at 100 celsius would not have activity as a result of temperature denaturation. This explains why the second test tube shows no enzyme activity, sucrase would must have denatured at 100 celsius.
<span>B, enzymes will denature at that temperature. Sucrase has an optimal temperature of about 37 degrees celsius so 1000 would definitely be too high for them to work.</span>
Explanation: When the rattlesnake population increases, the population of grasshopper and prairie dog are also decreases.
Both grasshopper and prairie dog are herbivores and eaten by rattlesnake. When rattlesnake population increases they feed on grasshopper and prairie dog and decrease occurs in their population.
