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4 years ago

Twice as number decreased by 9 is 7

Mathematics

1 answer:

marissa [1.9K]4 years ago

8 0

You said that. 2x - 9 = 7 . . . . . Add. 9. to each side: 2x = 16 . . . . . Divide each side by 2 : x = 8

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The volume of a cone-shaped hole is 50 pi ft cubed . If the hole is 6 ft deep, what is the radius of the hole?

True [87]

Answer:

r = 5

Step-by-step explanation:

The formula for volume of a cone is $\pi r^2*\frac{h}{3}$

h = 6

V = 50π

$2\pi r^2=50\pi$

r = 5

8 0

3 years ago

A store manager decides to clear out

azamat

Answer:

it would be A:55%

Step-by-step explanation

For percent, to make it easier try to turn it into a 100.

20x5=100

do the same to the 9.

9x5=45.

Now subtract 45 from 100.

100-45=55.

There was a discount of 55%.

7 0

3 years ago

The art museum had a total of 22for visitors on Tuesday. Visitors older than 18 paid $12 for admission. Visitors 18 years or you

Firlakuza [10]

Answer:

42 im pretty sure

Step-by-step explanation:

4 0

3 years ago

What do the following terms mean: is equal the same as = or x or - or +

JulsSmile [24]

Blue: = because the equal sign is stating that it’s the same.

7 0

3 years ago

Read 2 more answers

The manufacturer of a CD player has found that the revenue R (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com

AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

$R(p) = -5p^2 + 1550p$

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

$\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550$

Equating the first derivative to zero, we get,

$\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155$

Again differentiation R(p), with respect to p, we get,

$\dfrac{d^2(R(p))}{dp^2} = -10$

At p = 155

$\dfrac{d^2(R(p))}{dp^2} < 0$

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

$R(155) = -5(155)^2 + 1550(155) = 120125$

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0

3 years ago