If the average of 12 consecutive odd integers is 328, what is the least of these integers
1 answer:
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Answer:
No solution or
(-3±)/8
Step-by-step explanation:
To get the solution, move everything to the left side of the equation:
8x²+6x+5 = 0
If you try to factor the equation or graph it, you will see that it will never equal 0.
If you need an imaginary solution you can plug it into the quadratic equation:
-6± over 16
Simplify and you get
-6± over 16
-6± over 16
Simplify the fraction and you can get
(-3±)/8
