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3 years ago

If the average of 12 consecutive odd integers is 328, what is the least of these integers

1 answer:

5 0

X+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10+x+11+x+12/12
12x+78/12 = 132 times 12 is
12x+78 = 1,548 minus 78
12x = 1,506 divide by 12
x = 125.5 I believe is the answer, sorry if it is wrong

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Irina-Kira [14]

Answer:

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Step-by-step explanation:

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3 years ago

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Reil [10]

Answer:

Look to the explanation

Step-by-step explanation:

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3 years ago

Simplify the expression: 4(x + 3) + 3(5 – x) A X + 27 B X + 8 C 2x + 15 D. 19x + 11

Jobisdone [24]

Answer:

Step-by-step explanation:

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2 years ago

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Answer:

option-C

Step-by-step explanation:

We are given row-echelon form

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$y-4z=-5$

Let's assume

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now, we can find x and y

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$y=4t-5$

so, we get solutions as

$x=5t-3$

$y=4t-5$

$z=t$

where t can be any real numbers

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3 years ago

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a_sh-v [17]

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