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UkoKoshka [18]
4 years ago
11

The completed construction of a regular hexagon is shown below. Explain why ACF is a 30º-60º-90º triangle.

Mathematics
1 answer:
LuckyWell [14K]4 years ago
5 0

We know that one regular hexagon is consist of the six equilateral triangles.

One of this is ΔAFM every angle in this triangle worth 60°, according to this

∡AFM=60°.

ΔABC is isosceles triangle with angle ∡ABC=120°, because every interior angle in regular hexagon worth 120°.

Angles ∡BAC=∡BCA=30°. Total sum of angles in one triangle is 180°.

∡ACF≅∡BCA=30° at the end we can conclud that angle ∡FAC=90° WHY?

Good luck!!!

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