What would f(-5.2) equal if f(x)=[[x]]
1 answer:
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We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is
(x²/49)+(y²/4)=1
see the attached figure
Answer:
Option (4). y = 3x - 5
Step-by-step explanation:
Given question is incomplete; here is the complete question.
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
y = –1/3x + 5
y = –1/3x + 3
y = 3x + 2
y = 3x − 5
Line given in the graph passes through the points (-3, 2) and (0, 1).
Slope of the given line =
m =
m =
Let the equation of a line perpendicular to this line is,
y - y' = m'(x - x') [Given line passes through (x', y')]
By the property of perpendicular lines,
m × m' = -1
() × m' = -1
m' = 3
Equation of the perpendicular line will be,
y - 4 = 3(x - 3)
y - 4 = 3x - 9
y = 3x - 5
Option (4) will be the answer.
