Solve each of the equations independently, then determine if the are continuous or discontinuous.
15≥-3x [start here]
-5≤x [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5 [just turned around for analysis]
Next equation:
2/3x≥-2 [start here]
x≥-2(3/2) [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3
So, (according to the first equation) all values of x must be greater than, or equal to -5.
(According to the second equation) all values of x must be greater than, or equal to -3.
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.
So the question is asking: (x-4)(x-2)
because there is a bracket in between the two expressions it means we have to multiply them together: (x-4) x (x-2)
you can break down the question into smaller parts:
x multiply x
x multiply -2
-4 multiply x
-4 multiply -2
here are the answers:
x^2 (means x squared)
-2x
-4x
8 (because when you multiply two negative numbers it makes a positive)
now you put it into an expression (this is expanding):
x^2 - 2x - 4x + 8
to simplify it you collect like terms:
x^2 - 6x + 8
The above is the answer :)
Answer:
8
Step-by-step explanation:
2^2+2(4-2)
4+8-4
8
Hope this helps :D
To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.
Answer:
, 12, 48, 192...
a. Write a recursive formula for the nth term of the sequence
Ans: a(n+1) = 4*a(n)
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b. Write a general formula for the nth term of the sequence
a(n) = 3*4^(n-1)
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c. Calculate S10 for this sequence
Geometric sequence with a(1) = 3 and r = 4
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Step-by-step explanation:
