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2 years ago

What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?

Mathematics

1 answer:

Kipish [7]2 years ago

4 0

-4x/5+8.8. I think that's it, and if it isn't, i don't know.

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I need help determining how to use the graph or table and write/ match a linear function that relates y to x

BabaBlast [244]

Answer:

y = 3/2x

Step-by-step explanation:

The slope goes up by 3 and to the right by 2, using rise/run slope rule, then the slope is 3/2

6 0

3 years ago

Evaluate 1+ (-2/3)- (-m) where m=9/12

Agata [3.3K]

Answer:

13/12

Step-by-step explanation:

1-2/3+9/12

least common denominator is 12

12/12 - 8/12+9/12

13/12

6 0

2 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago

D divided bye 1.4=2.3 what is d

kati45 [8]

Multiply 2.3 by 1.4= D

4 0

3 years ago

Read 2 more answers

A rectangular swimming pool has a base of 200 square feet. The pool has a depth of 5 feet.

xz_007 [3.2K]

Answer:

1,000 ft³

Step-by-step explanation:

The volume is given by ...

V = Bh

where B is the area of the base, and h is the height. For the given dimensions, the volume is ...

V = (200 ft²)(5 ft) = 1000 ft³

3 0

2 years ago