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Kruka [31]
3 years ago
14

20 POINTS!! Which ordered pair is the solution to the system of equations?

Mathematics
1 answer:
marta [7]3 years ago
8 0
Hello! I would love to help!

The answer is -10,-1

Basically, you have to fill -10 in for x and -1 in for y in each equation. If the equations are true, that is the right answer!


Hope this helped! Comment if you have questions!







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Which equation matches the graph of the greatest integer function given below?? help pleaze
Alex787 [66]
The correct answer is C
4 0
4 years ago
Read 2 more answers
A taxi charges a flat rate of R10, and an additional cost of 30 cents per kilometer. If you have
Maslowich

Step-by-step explanation:

so, just by getting into the taxi we have to pay R10.

that leaves us 22 - 10 = R12 for the actual trip.

30 cents per kilometer.

so, how many units of 30 cents are there in R12 ? that is the number of kilometers we can go.

R12 = 1200 cent (right ?)

1200 / 30 = 120 / 3 = 40

so, we can travel 40 kilometers for that money.

8 0
3 years ago
Allan borrows 1870 dollars from his uncle. Two years later, he borrows another 1240 dollars. If his uncle charges him 8 percent
Anna11 [10]
For t=0
<span>Allan borrows--------------------------- > 1870 dollars

for t=6 years
</span>F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars

for t=2
Allan borrows--------------------------- > 1240 dollars

for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars

F1+F2=2967.45+1687=4654.45 dollars
the answer is 4654.45 dollars


3 0
3 years ago
Find the total amount and amount of interest paid in the following compound interest problems. $900 at 6%, for 10 years.
Naddik [55]
Your monthly payment would be $9.99 that is your answer to your question. 

I hope this is what you are looking for have i nice week

8 0
4 years ago
PLEASE HELP HELP ASAP ASAPP WILL GIVE 100 POINTS AND BRAINLEST! PLUS MY THANKS AND ADMIRATION PLEASE PLEASE!!
tatyana61 [14]

Answer:

First Picture ⇒ [B] <em>a = -2, b = 1, and c = -5</em>

<em>Second Picture ⇒ First step: Identify a = 1, b = 3, c = -4</em>

<em>                           </em>x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

<em>                              </em>x=\frac{-3\pm 5\sqrt{25}}{2}

                           x=\frac{-3\pm \:5}{2}

                        x=\frac{-3+5}{2},\:x=\frac{-3-5}{2\c}

Third Picture ⇒ Missing Info

Fourth Picture ⇒ [A] x=-\frac{5}{2},\:x=-3

Fifth Picture ⇒ x=\frac{5\pm\sqrt{1} }{2}

Step-by-step explanation:

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Identify the a,b, and c-values for this equation:</em>

<em>y = -2x²  + x -5  </em>

<em>Quadratic Formula:</em>

<em>ax²+bx+c=0</em>

<em>−2x²+1x−5=0</em>

<em>a = -2, b = 1, and c = -5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

Order the steps for solving this equation using the quadratic formula.

x<em>²  + 3x - 4 = 0</em>

<em>Solving to see what are the steps:</em>

<em>First step: Identify a = 1, b = 3, c = -4</em>

<em />x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

x=\frac{-3\pm 5\sqrt{25}}{2}

x=\frac{-3\pm \:5}{2}

x_1=\frac{-3+5}{2\cdot \:1},\:x_2=\frac{-3-5}{2\cdot \:1}

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Use the quadratic formula to find the solution set for 2x² + 15 = -11x.</em>

<em>Add 11x to both sides:</em>

<em>2x² + 15+11x = -11x+11x</em>

<em>Simplify</em>

<em>2x² + 11x+15 = 0</em>

<em>Now solve with quadratic formula..</em>

<em />x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}

x_{1,\:2}=\frac{-11\pm \:1}{2\cdot \:2}

x_1=\frac{-11+1}{2\cdot \:2},\:x_2=\frac{-11-1}{2\cdot \:2}

x=-\frac{5}{2},\:x=-3

Hence, [A] x=-\frac{5}{2},\:x=-3

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Suppose you are solving a quadratic equation and this is your work so far...</em>

<em>x  ²  - 5x + 6 = 0</em>

<em>Thus, we have:</em>

<em />x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}

x=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}

x=\frac{5\pm\sqrt{1} }{2}

x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}

x=3,x=2

<em>-------------------------------------------------------------------------------------------------------------</em>

<u><em>Kavinsky</em></u>

6 0
2 years ago
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