Ask question

Ask question

All categories

3 years ago

15

–3.4 + (–8 + 2) = [ ? + (–8)] + 2 whats the missing number

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

I suppose what makes this question annoying is that there is the question mark so what i'll do first is substitute the question mark with x. also, there are annoying parenthesis so we'll first eliminate the ones we don't need. now we just have to solve for x. -3.4 + (-8 + 2) = (x + (-8)) + 2 adding a negative number is subtracting that number so x + (-8) = x - 8 -3.4 + 2 - 8 = x - 8 + 2 -3.4 -6 = x - 6 x = -3.4 make sure you are aware that the negative sign belongs to the number after it so -2 + 4 is not -(2+4) = -6 but rather 4 - 2 = 2. let me know if you have any questions!

You might be interested in

A box dozen fruit tarts cost $15 what is the cost of one fruit tart

Anna007 [38]

One dozen = 12

15/12 = 1.25

The cost of one fruit tart is $1.25

7 0

3 years ago

Read 2 more answers

What number is 100,000 more than 75,000 and explain how u got answer

alina1380 [7]

100,000 + 75,000 = 175,000. To get the answer, you add the two.

6 0

3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

The area of a rectangle is represented by the expression 6x³y5. Which of the following could be the

oee [108]

The length and width of the rectangle are: $2x^2y^2 , 3xy^3$

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

The area of a rectangle is represented by the expression $6x^3y^5$ .

The area of the rectangle = $2x^2y^2 \times 3xy^3$

= $6x^3y^5$

So, the length and width of the rectangle are: $2x^2y^2 , 3xy^3$

Learn more about the area;

brainly.com/question/1658516

#SPJ1

7 0

1 year ago

in a fish bowl there were 12 fish, some little, others big. if each of the big fish ate 2 little fish and then the little fish w

Charra [1.4K]

There will be 4 big fish left.

3 0

3 years ago

Read 2 more answers