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3 years ago

15

–3.4 + (–8 + 2) = [ ? + (–8)] + 2 whats the missing number

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

I suppose what makes this question annoying is that there is the question mark so what i'll do first is substitute the question mark with x. also, there are annoying parenthesis so we'll first eliminate the ones we don't need. now we just have to solve for x. -3.4 + (-8 + 2) = (x + (-8)) + 2 adding a negative number is subtracting that number so x + (-8) = x - 8 -3.4 + 2 - 8 = x - 8 + 2 -3.4 -6 = x - 6 x = -3.4 make sure you are aware that the negative sign belongs to the number after it so -2 + 4 is not -(2+4) = -6 but rather 4 - 2 = 2. let me know if you have any questions!

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Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type your answers in the box. ƒ -

katrin2010 [14]

As you know, to get the inverse of any expression, we start off by switching the variables about and then solving for "y",

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3 years ago

Graph the Quadratic Function given.<br> y = -x^2 - 4x - 3

Dovator [93]

Answer:

Concave down

Y-intercept: (0,-3)

X-intercepts: (-1,0) (-3,0)

Vertex: (-2,1)

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3 years ago

How to simplify 24yz^5/32y^2z

Maurinko [17]

24y*z^5/32y^2*z

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3 years ago

What is the exact circumference of a circle with a radius of 125 m? Use 3.14 to approximate pi

djyliett [7]

Answer:

B. 785 M

Step-by-step explanation:

Circumference = 2*pi*r

C = 2 * pi * 125

C = 250pi This is the exact answer

Now approximating with pi as 3.14

C = 250 (3.14)

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4 0

3 years ago

Read 2 more answers

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

3 0

3 years ago